0=x^2-10x+4

Solution for 0=x^2-10x+4 equation:

0=x^2-10x+4

We move all terms to the left:

0-(x^2-10x+4)=0

We add all the numbers together, and all the variables

-(x^2-10x+4)=0

We get rid of parentheses

-x^2+10x-4=0

We add all the numbers together, and all the variables

-1x^2+10x-4=0

a = -1; b = 10; c = -4;
Δ = b2-4ac
Δ = 102-4·(-1)·(-4)
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{21}}{2*-1}=\frac{-10-2\sqrt{21}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{21}}{2*-1}=\frac{-10+2\sqrt{21}}{-2}
$